因式分解a2x2+b2y2-2ax-2by+2abxy,x3+6x2+11x+6.x2+6xy+9y2-16x-48y...

发布网友 发布时间：2024-10-23 12:50

我来回答

共3个回答

热心网友 时间：12小时前

a2x2+b2y2-2ax-2by+2abxy
=[(ax)²+2*(ax)*(by)+(by)²]-2(ax+by)
=(ax+by)²-2(ax+by)
=(ax+by)(ax+by-2)

x3+6x2+11x+6
=x³+6x²+9x+2x+6
=x(x²+6x+9)+2(x+3)
=x(x+3)²+2(x+3)
=(x+3)(x²+3x+2)
=(x+1)(x+2)(x+3)

.x2+6xy+9y2-16x-48y-36
=(x+3y)²-16(x+3y)-36
=(x+3y-18)(x+3y+2)

热心网友 时间：12小时前

a2x2+b2y2-2ax-2by+2abxy
=(a2x2+2abxy+b2y2)-(2ax+2by)
=(ax+by)^2-2(ax+by)
=(ax+by)(ax+by-2)

x3+6x2+11x+6
=x^3+x^2+5x^2+5x+6x+6
=x^2(x+1)+5x(x+1)+6(x+1)
=(x+1)(x^2+5x+6)
=(x+1)(x+2)(x+3)

x2+6xy+9y2-16x-48y-36
=(x^2+6xy+9y^2)-(16x+48y)-36
=(x+3y)^2-16(x+3y)-36
=(x+3y+2)(x+3y-18)

热心网友 时间：12小时前

a2x2+b2y2-2ax-2by+2abxy=(ax+by)2-2(ax+by)=(ax+by)(ax+by-2)